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Practice Problems 11

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Q 1. y = 4s +I 3s+ 2y = 13 2.2. z +4y = 14 2z — y = 1 5x + 3y = 1 3x + 4y = —6

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1.Substitute 4z +1 for y in the i 3 + 2(4 +1) = 13 3 + 8z + 2 = 13 1Ix = 11 = 1 y —— 4(1) +1 = 5 The solution set is { (1,5)) . 2.Multiply the second equation equation. z + 4y = 142(2)— \ = I —\ = —3 \ = 3 The solution set is { (2,3)) .